- List the pile which classified according to the material used for construction, then
discuss indetail the advantage and disadvantage of these type of pile.
- What will happen if you install driven pile in clay and sandy soil?
- Describe collapsible soil and its nature under load
- Explain the difference between shallow foundation and deep foundation?
- Define Negative skin Friction. How it developed?
- A concrete pile is 16m long and 400mm X 400mm cross section The pile is fully
embedded in sand forwhich unit weight of soil γ= 18kN/m3
and ϕ=30o Calculate
ultimate point load, Qp by
- Meyerhof’s method
- Vesic method if Es=20.5MN/m2 μs=0.3 for sand
III. Janbu method if η’ =900
, for this sand
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- A concrete pile is 16m long and 400mm X 400mm cross section The pile is fully
embedded in sand forwhich unit weight of soil γ= 18kN/m3
and ϕ=30o
- a) Determine the frictional resistance Qs using K=1.3 and δ =0.8ϕ
- b) Using the result Qp obtain from Ex 1, estimate the allowable load carrying capacity
of the pile.Take Fs=4
- A pile (closed end) that has been driven in to a layered sand is shown in figure 1
calculate:
- The ultimate point load by Meyerhof’s procedure
- The ultimate frictional resistance, Qs, use K = 1.4, and δ’= 0.7ϕ
- The allowable load of the pile, use FS = 4
- A concrete pile is driven into the strata shown in Fig 2. Based on data given in
Fig 2,determine ultimate point load, Qp by
- Meyerhof’s method
- Vesic’s method if Es =20MN/m2
- Janbu method if η =75
- Determine frictional resistance using the same data as shown in Fig 2 assuming that
the pile is high displacement driven pile and δ =0.7ϕ
- Determine allowable capacity of pile if FS =3.5
- A driven pile in clay shown in the following Fig, the pile has an outside diameter
of 400mm and wallthickness of 6.35mm.
- a) Calculate the net point bearing capacity of the pile
- b) Calculate skin friction by methods for clay layer. The top 10m of the clay is
normallyconsolidated. The bottom clay layer has an OCR =2
- c) Estimate the net allowable pile capacity if FS=4
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