Methane and water react to form carbon monoxide and hydrogen, like this: CH4(9)+H2O(g) → CO(g)+3H2(g) Imagine…


Methane and water react to form carbon monoxide and hydrogen, like this: CH4(9) H2O(g) → CO(g) 3H2(g) Imagine 61. mmol of CH4 and 61. mmol of H, O are added to an empty flask, and then answer the following questions. What is the rate of the forward reaction before any CH4 or H2O has been added to the flask? What is the rate of the forward reaction just after the CH4 and H2O has been added to the flask? Zero. O Greater than zero, but less than the rate of the reverse reaction. O Greater than zero, and equal to the rate of the reverse reaction. O Greater than zero, and greater than the rate of the reverse reaction. Zero. O Greater than zero, but less than the rate of the reverse reaction. O Greater than zero, and equal to the rate of the reverse reaction. O Greater than zero, and greater than the rate of the reverse reaction. Zero. O Greater than zero, but less than the rate of the reverse reaction. O Greater than zero, and equal to the rate of the reverse reaction. O Greater than zero, and greater than the rate of the reverse reaction. None. Some, but less than 61. mmol. 61. mmol. O More than 61. mmol. What is the rate of the forward reaction at equilibrium? How much CH, is in the flask at equilibrium?

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